57-71
wide K L1 L2 L3 |
57,
LA 0.31844 1.97800 2.10530 2.26100 |
58,
CE 0.30648 1.89340 2.01240 2.16600 |
59,
PR 0.29518 1.81410 1.92550 2.07910 |
60,
ND 0.28453 1.73900 1.84400 1.99670 |
61,
PM 0.27431 1.66740 1.76760 1.91910 |
62,
SM 0.26464 1.60020 1.69530 1.84570 |
63,
EU 0.25553 1.53810 1.62710 1.77610 |
64,
GD 0.24681 1.47840 1.56320 1.71170 |
65,
TB 0.23841 1.42230 1.50230 1.64970 |
66,
DY 0.23048 1.36920 1.44450 1.59160 |
67,
HO 0.22291 1.31900 1.39050 1.53680 |
68,
ER 0.21567 1.27060 1.33860 1.48350 |
69,
TM 0.20880 1.22500 1.28920 1.43340 |
70,
YB 0.20224 1.18180 1.24280 1.38620 |
71,
LU 0.19585 1.14020 1.19850 1.34050 |
89-103,
wide K L1 L2 L3 |
92,
U 0.10723 0.56950 0.59190 0.72226 |
Linear absorption coefficient
Linear absorption coefficient of materials defined by Eq (1).
I=I0
exp(-ux)
(1)
M A for the database is a atomic absorption coefficient for a crystal.
Using the atomic absorption coefficient for a crystal, we have
u=z sum(M A)i/(V
10-24)
(8)
where z is a chemical unit, V is the cell volume in Angstrom unit,
and the summation is taken over the constituent elements in the chemical
formula. For an exaple of tetragonal Tl2CaBa2Cu2O8 (z=2,V=435A3)
at the wavelength =0.5A, the linear-absorption coefficient is calculated
as u=196(cm-1).
Furthermore, the linear-absorption coefficient, u, can be calculated
from M/R as:
u=d sum(pi(M/R)i)
(9)
where d is the density (g/cm3) of the material,pi is the fractional
part(by weight) of the constituent elements of the compound, and
the summation is taken over all elements. The u value of the tungsten having
the density of 19.24 g/cm3 is calculated at wavelength=0.5 A as u=~687
(cm-1).